Template:Photo of art
Revision as of 22:15, 19 June 2020 by Wikipedia>Brainulator9 (clarifying the second license being for the original copyrighted work; also fixing a bit of grammar)
 | This image is a derivative work of separately copyrighted work. It is, therefore, treated on Wikipedia as non-free and each use within an article must satisfy the non-free content criteria. Re-users of this content, in addition to needing a fair use or similar legal claim to use the depiction of the copyrighted work, must also respect the rights of the derivative author by complying with that author's chosen free license terms. If this image is of an artwork on display in a public location in a jurisdiction that permits freedom of panorama (such as the UK), then please remove {{Photo of art}} tag, placing the photographer's 'free' license in this section of the media description page |
 | Do not copy this file to Wikimedia Commons. The subject of this image is still protected by copyright. Commons does not accept 'fair-use' images. |
Template documentationThis template is used to mark an image which is a photo of an artwork subject to a copyright status separate from the photo of it.
This tag should not be used where Freedom of Panorama would apply.
Usage
{{Photo of art|1|2|3}}
Parms
{{{1}}}- The licence tag used by the uploader/author for the photo{{{2}}}- Desired attribution for the author{{{3}}}- The license for the work shown{{{pdsource}}}- If both licenses are 'free' then set yes to mark the image suitable for Commons.{{{nowcommons}}}- Filename.ext of the media or file on Wikimedia Commons, will generate an F8 notice if added.