Module:Years generator

local p = {} --p stands for package

function p.templateEveryYearToPresent ( frame ) -- use the parent args if available, assuming this is embedded in a template parentArgs = frame:getParent.args argsToUse = ((parentArgs[1] and parentArgs) or frame.args) years = yearsFromYearToPresent( argsToUse[1] ) toReturn = "" templateArgs = {} templateDoNotConsume = {} -- allow transcluding templates to specify arguments they consume, -- so we should ignore them for arg in mw.text.gsplit( frame.args['templatedonotconsume'] or '', ',', true ) do templateDoNotConsume[arg] = true end for key, arg in pairs( argsToUse ) do		-- taking everything beyond the second arg, we pass it onto the template -- this includes named args, so we don't want to just do &#x3e; 2 if (			key ~= 1			and key ~= 2			and not templateDoNotConsume[key]			) then numericKey = tonumber( key ) if ( numericKey ) then -- templateArgs[1] will always be the year (lua arrays start at 1) -- templateArgs[2] should be the first other template param -- which is args[3], so we have here [key - 1] templateArgs[key - 1] = arg else -- named params we just shove in				templateArgs[key] = arg end end end for index, year in ipairs( years ) do		templateArgs[1] = tostring( year ) toReturn = toReturn .. ( index == 0 and '' or '&#x3c;br /&#x3e;' ) .. "&#x3c;strong&#x3e;" .. templateArgs[1] .. "&#x3c;/strong&#x3e; &#x26;mdash; " -- if parentArgs is used, then frame.args[1] will be the template, -- as no other args are going to be in the immediate frame. if	   -- there are no parentArgs, then it'll be the second param, -- because the year will have been directly passed to the module .. frame:expandTemplate{ title = ((parentArgs[1] and frame.args[1]) or frame.args[2]), args = templateArgs } end return toReturn end

function yearsFromYearToPresent( year ) startyear = tonumber( year ) if ( startyear == nil ) then error( "Invalid start year provided" ) end years = {} numyears = ( tonumber( os.date( "%Y" ) ) - startyear ) for numadded = 0, numyears do -- equiv of i = 0; i &#x3c;= numyears; i++ years[numadded + 1] = startyear + numadded end return years end

return p